# Blogs Hub

### by Sumit Chourasia | Sep 27, 2020 | Category :coding | Tags : algorithmarrayडेटा-संरचनाआसानleetcode

#### Count Good Triplets - Array - Easy - LeetCode - मिनी टीवी

Given an array of integers arr, and three integers a, b and c. You need to find the number of good triplets.

A triplet (arr[i], arr[j], arr[k]) is good if the following conditions are true:

0 <= i < j < k < arr.length
|arr[i] - arr[j]| <= a
|arr[j] - arr[k]| <= b
|arr[i] - arr[k]| <= c
Where |x| denotes the absolute value of x.

Return the number of good triplets.

Example 1:

Input: arr = [3,0,1,1,9,7], a = 7, b = 2, c = 3
Output: 4
Explanation: There are 4 good triplets: [(3,0,1), (3,0,1), (3,1,1), (0,1,1)].
Example 2:

Input: arr = [1,1,2,2,3], a = 0, b = 0, c = 1
Output: 0
Explanation: No triplet satisfies all conditions.

Constraints:

3 <= arr.length <= 100
0 <= arr[i] <= 1000
0 <= a, b, c <= 1000

``````public class Solution {
public int CountGoodTriplets(int[] arr, int a, int b, int c) {
int count = 0;
for(int i=0;i<arr.Length;i++){
for(int j=i+1;j<arr.Length;j++){
if(Math.Abs(arr[i]-arr[j])>a){
continue;
}
for(int k=j+1;k<arr.Length;k++){
if(
(Math.Abs(arr[j]-arr[k])<=b)&&
(Math.Abs(arr[i]-arr[k])<=c)
)
{
count++;
}
}
}
}

return count;
}
}``````

Time Complexity: O(n^3)

Space Complexity: O(1)

Contributed By: Sumit Chourasia
Contributed By: Sumit Chourasia
Contributed By: Sumit Chourasia
Contributed By: Sumit Chourasia