Blogs Hub

Largest Number At Least Twice of Others - MiniTV

Largest Number At Least Twice of Others - मिनी टीवी

In a given integer array nums, there is always exactly one largest element.

Find whether the largest element in the array is at least twice as much as every other number in the array.

If it is, return the index of the largest element, otherwise, return -1.

Example 1:

Input: nums = [3, 6, 1, 0]
Output: 1
Explanation: 6 is the largest integer and for every other number in the array x,
6 is more than twice as big as x.  The index of value 6 is 1, so we return 1.
 

Example 2:

Input: nums = [1, 2, 3, 4]
Output: -1
Explanation: 4 isn't at least as big as twice the value of 3, so we return -1.

public class Solution {
    public int DominantIndex(int[] nums) {
        int max = -1;
        int index = -1;
        int second = -1;
        
        for(int i=0;i<nums.Length;i++){
            if(nums[i]>max){
                second = max;
                max = nums[i];
                index = i;
            }
            else if(nums[i]>second){
                second = nums[i];
            }
        }            
        
        return second*2<=max?index:-1;
    }
}

 


Time Complexity: O(n)

Space Complexity: O(1)