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by Sumit Chourasia | May 03, 2020 | Category :coding | Tags : leetcode आसान algorithm string

Generate a String With Characters That Have Odd Counts - MiniTV

Generate a String With Characters That Have Odd Counts - मिनी टीवी

Given an integer n, return a string with n characters such that each character in such string occurs an odd number of times.

The returned string must contain only lowercase English letters. If there are multiples valid strings, return any of them.  

 

Example 1:

Input: n = 4

Output: "pppz"

Explanation: "pppz" is a valid string since the character 'p' occurs three times and the character 'z' occurs once. Note that there are many other valid strings such as "ohhh" and "love".

 

Example 2:

Input: n = 2

Output: "xy"

Explanation: "xy" is a valid string since the characters 'x' and 'y' occur once. Note that there are many other valid strings such as "ag" and "ur".

 

Example 3:

Input: n = 7

Output: "holasss"

 

Constraints:

1 <= n <= 500

 

Solution:

using System;
using System.Collections.Generic;
using System.Text;

namespace LeetCode.AskGif.Easy.String
{
    class GenerateTheStringSoln
    {
        public void execute()
        {
            var res = GenerateTheString(5);
        }

        public string GenerateTheString(int n)
        {
            StringBuilder str = new StringBuilder();
            if (n % 2 == 0)
            {
                for(int i = 0; i < n - 1; i++)
                {
                    str.Append("a");
                }
                str.Append("b");
            }
            else
            {
                for (int i = 0; i < n; i++)
                    str.Append("c");
            }

            return str.ToString();
        }
    }
}

 

Time Complexity: O(n) - For appending n characters in the string

Space Complexity: O(1) - No Extra space